3.7.80 \(\int \frac {x^{10}}{(a+c x^4)^3} \, dx\) [680]

Optimal. Leaf size=223 \[ -\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}-\frac {21 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {21 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}} \]

[Out]

-1/8*x^7/c/(c*x^4+a)^2-7/32*x^3/c^2/(c*x^4+a)+21/128*arctan(-1+c^(1/4)*x*2^(1/2)/a^(1/4))/a^(1/4)/c^(11/4)*2^(
1/2)+21/128*arctan(1+c^(1/4)*x*2^(1/2)/a^(1/4))/a^(1/4)/c^(11/4)*2^(1/2)+21/256*ln(-a^(1/4)*c^(1/4)*x*2^(1/2)+
a^(1/2)+x^2*c^(1/2))/a^(1/4)/c^(11/4)*2^(1/2)-21/256*ln(a^(1/4)*c^(1/4)*x*2^(1/2)+a^(1/2)+x^2*c^(1/2))/a^(1/4)
/c^(11/4)*2^(1/2)

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Rubi [A]
time = 0.11, antiderivative size = 223, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {294, 303, 1176, 631, 210, 1179, 642} \begin {gather*} -\frac {21 \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}+1\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {21 \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}-\frac {x^7}{8 c \left (a+c x^4\right )^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^10/(a + c*x^4)^3,x]

[Out]

-1/8*x^7/(c*(a + c*x^4)^2) - (7*x^3)/(32*c^2*(a + c*x^4)) - (21*ArcTan[1 - (Sqrt[2]*c^(1/4)*x)/a^(1/4)])/(64*S
qrt[2]*a^(1/4)*c^(11/4)) + (21*ArcTan[1 + (Sqrt[2]*c^(1/4)*x)/a^(1/4)])/(64*Sqrt[2]*a^(1/4)*c^(11/4)) + (21*Lo
g[Sqrt[a] - Sqrt[2]*a^(1/4)*c^(1/4)*x + Sqrt[c]*x^2])/(128*Sqrt[2]*a^(1/4)*c^(11/4)) - (21*Log[Sqrt[a] + Sqrt[
2]*a^(1/4)*c^(1/4)*x + Sqrt[c]*x^2])/(128*Sqrt[2]*a^(1/4)*c^(11/4))

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 294

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^
n)^(p + 1)/(b*n*(p + 1))), x] - Dist[c^n*((m - n + 1)/(b*n*(p + 1))), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 303

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 631

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[a*(c/b^2)]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 642

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[d*(Log[RemoveContent[a + b*x +
c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1176

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[2*(d/e), 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1179

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[-2*(d/e), 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {x^{10}}{\left (a+c x^4\right )^3} \, dx &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}+\frac {7 \int \frac {x^6}{\left (a+c x^4\right )^2} \, dx}{8 c}\\ &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}+\frac {21 \int \frac {x^2}{a+c x^4} \, dx}{32 c^2}\\ &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}-\frac {21 \int \frac {\sqrt {a}-\sqrt {c} x^2}{a+c x^4} \, dx}{64 c^{5/2}}+\frac {21 \int \frac {\sqrt {a}+\sqrt {c} x^2}{a+c x^4} \, dx}{64 c^{5/2}}\\ &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}+\frac {21 \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{128 c^3}+\frac {21 \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{128 c^3}+\frac {21 \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}+2 x}{-\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}-2 x}{-\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}\\ &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}+\frac {21 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {21 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {21 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}\\ &=-\frac {x^7}{8 c \left (a+c x^4\right )^2}-\frac {7 x^3}{32 c^2 \left (a+c x^4\right )}-\frac {21 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} \sqrt [4]{a} c^{11/4}}+\frac {21 \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}-\frac {21 \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{128 \sqrt {2} \sqrt [4]{a} c^{11/4}}\\ \end {align*}

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Mathematica [A]
time = 0.06, size = 205, normalized size = 0.92 \begin {gather*} \frac {\frac {32 a c^{3/4} x^3}{\left (a+c x^4\right )^2}-\frac {88 c^{3/4} x^3}{a+c x^4}-\frac {42 \sqrt {2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{\sqrt [4]{a}}+\frac {42 \sqrt {2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{\sqrt [4]{a}}+\frac {21 \sqrt {2} \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{\sqrt [4]{a}}-\frac {21 \sqrt {2} \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{\sqrt [4]{a}}}{256 c^{11/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^10/(a + c*x^4)^3,x]

[Out]

((32*a*c^(3/4)*x^3)/(a + c*x^4)^2 - (88*c^(3/4)*x^3)/(a + c*x^4) - (42*Sqrt[2]*ArcTan[1 - (Sqrt[2]*c^(1/4)*x)/
a^(1/4)])/a^(1/4) + (42*Sqrt[2]*ArcTan[1 + (Sqrt[2]*c^(1/4)*x)/a^(1/4)])/a^(1/4) + (21*Sqrt[2]*Log[Sqrt[a] - S
qrt[2]*a^(1/4)*c^(1/4)*x + Sqrt[c]*x^2])/a^(1/4) - (21*Sqrt[2]*Log[Sqrt[a] + Sqrt[2]*a^(1/4)*c^(1/4)*x + Sqrt[
c]*x^2])/a^(1/4))/(256*c^(11/4))

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Maple [A]
time = 0.15, size = 131, normalized size = 0.59

method	result	size
risch	\(\frac {-\frac {11 x^{7}}{32 c}-\frac {7 a \,x^{3}}{32 c^{2}}}{\left (x^{4} c +a \right )^{2}}+\frac {21 \left (\munderset {\textit {\_R} =\RootOf \left (c \,\textit {\_Z}^{4}+a \right )}{\sum }\frac {\ln \left (x -\textit {\_R} \right )}{\textit {\_R}}\right )}{128 c^{3}}\)	\(56\)
default	\(\frac {-\frac {11 x^{7}}{32 c}-\frac {7 a \,x^{3}}{32 c^{2}}}{\left (x^{4} c +a \right )^{2}}+\frac {21 \sqrt {2}\, \left (\ln \left (\frac {x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}{x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{256 c^{3} \left (\frac {a}{c}\right )^{\frac {1}{4}}}\)	\(131\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^10/(c*x^4+a)^3,x,method=_RETURNVERBOSE)

[Out]

(-11/32/c*x^7-7/32/c^2*a*x^3)/(c*x^4+a)^2+21/256/c^3/(1/c*a)^(1/4)*2^(1/2)*(ln((x^2-(1/c*a)^(1/4)*x*2^(1/2)+(1
/c*a)^(1/2))/(x^2+(1/c*a)^(1/4)*x*2^(1/2)+(1/c*a)^(1/2)))+2*arctan(2^(1/2)/(1/c*a)^(1/4)*x+1)+2*arctan(2^(1/2)
/(1/c*a)^(1/4)*x-1))

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Maxima [A]
time = 0.51, size = 215, normalized size = 0.96 \begin {gather*} -\frac {11 \, c x^{7} + 7 \, a x^{3}}{32 \, {\left (c^{4} x^{8} + 2 \, a c^{3} x^{4} + a^{2} c^{2}\right )}} + \frac {21 \, {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{\sqrt {\sqrt {a} \sqrt {c}} \sqrt {c}} + \frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{\sqrt {\sqrt {a} \sqrt {c}} \sqrt {c}} - \frac {\sqrt {2} \log \left (\sqrt {c} x^{2} + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {1}{4}} c^{\frac {3}{4}}} + \frac {\sqrt {2} \log \left (\sqrt {c} x^{2} - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {1}{4}} c^{\frac {3}{4}}}\right )}}{256 \, c^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10/(c*x^4+a)^3,x, algorithm="maxima")

[Out]

-1/32*(11*c*x^7 + 7*a*x^3)/(c^4*x^8 + 2*a*c^3*x^4 + a^2*c^2) + 21/256*(2*sqrt(2)*arctan(1/2*sqrt(2)*(2*sqrt(c)
*x + sqrt(2)*a^(1/4)*c^(1/4))/sqrt(sqrt(a)*sqrt(c)))/(sqrt(sqrt(a)*sqrt(c))*sqrt(c)) + 2*sqrt(2)*arctan(1/2*sq
rt(2)*(2*sqrt(c)*x - sqrt(2)*a^(1/4)*c^(1/4))/sqrt(sqrt(a)*sqrt(c)))/(sqrt(sqrt(a)*sqrt(c))*sqrt(c)) - sqrt(2)
*log(sqrt(c)*x^2 + sqrt(2)*a^(1/4)*c^(1/4)*x + sqrt(a))/(a^(1/4)*c^(3/4)) + sqrt(2)*log(sqrt(c)*x^2 - sqrt(2)*
a^(1/4)*c^(1/4)*x + sqrt(a))/(a^(1/4)*c^(3/4)))/c^2

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Fricas [A]
time = 0.39, size = 240, normalized size = 1.08 \begin {gather*} -\frac {44 \, c x^{7} + 28 \, a x^{3} + 84 \, {\left (c^{4} x^{8} + 2 \, a c^{3} x^{4} + a^{2} c^{2}\right )} \left (-\frac {1}{a c^{11}}\right )^{\frac {1}{4}} \arctan \left (-c^{3} x \left (-\frac {1}{a c^{11}}\right )^{\frac {1}{4}} + \sqrt {-a c^{5} \sqrt {-\frac {1}{a c^{11}}} + x^{2}} c^{3} \left (-\frac {1}{a c^{11}}\right )^{\frac {1}{4}}\right ) - 21 \, {\left (c^{4} x^{8} + 2 \, a c^{3} x^{4} + a^{2} c^{2}\right )} \left (-\frac {1}{a c^{11}}\right )^{\frac {1}{4}} \log \left (a c^{8} \left (-\frac {1}{a c^{11}}\right )^{\frac {3}{4}} + x\right ) + 21 \, {\left (c^{4} x^{8} + 2 \, a c^{3} x^{4} + a^{2} c^{2}\right )} \left (-\frac {1}{a c^{11}}\right )^{\frac {1}{4}} \log \left (-a c^{8} \left (-\frac {1}{a c^{11}}\right )^{\frac {3}{4}} + x\right )}{128 \, {\left (c^{4} x^{8} + 2 \, a c^{3} x^{4} + a^{2} c^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10/(c*x^4+a)^3,x, algorithm="fricas")

[Out]

-1/128*(44*c*x^7 + 28*a*x^3 + 84*(c^4*x^8 + 2*a*c^3*x^4 + a^2*c^2)*(-1/(a*c^11))^(1/4)*arctan(-c^3*x*(-1/(a*c^
11))^(1/4) + sqrt(-a*c^5*sqrt(-1/(a*c^11)) + x^2)*c^3*(-1/(a*c^11))^(1/4)) - 21*(c^4*x^8 + 2*a*c^3*x^4 + a^2*c
^2)*(-1/(a*c^11))^(1/4)*log(a*c^8*(-1/(a*c^11))^(3/4) + x) + 21*(c^4*x^8 + 2*a*c^3*x^4 + a^2*c^2)*(-1/(a*c^11)
)^(1/4)*log(-a*c^8*(-1/(a*c^11))^(3/4) + x))/(c^4*x^8 + 2*a*c^3*x^4 + a^2*c^2)

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Sympy [A]
time = 0.25, size = 70, normalized size = 0.31 \begin {gather*} \frac {- 7 a x^{3} - 11 c x^{7}}{32 a^{2} c^{2} + 64 a c^{3} x^{4} + 32 c^{4} x^{8}} + \operatorname {RootSum} {\left (268435456 t^{4} a c^{11} + 194481, \left ( t \mapsto t \log {\left (\frac {2097152 t^{3} a c^{8}}{9261} + x \right )} \right )\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**10/(c*x**4+a)**3,x)

[Out]

(-7*a*x**3 - 11*c*x**7)/(32*a**2*c**2 + 64*a*c**3*x**4 + 32*c**4*x**8) + RootSum(268435456*_t**4*a*c**11 + 194
481, Lambda(_t, _t*log(2097152*_t**3*a*c**8/9261 + x)))

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Giac [A]
time = 0.51, size = 206, normalized size = 0.92 \begin {gather*} -\frac {11 \, c x^{7} + 7 \, a x^{3}}{32 \, {\left (c x^{4} + a\right )}^{2} c^{2}} + \frac {21 \, \sqrt {2} \left (a c^{3}\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (2 \, x + \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{128 \, a c^{5}} + \frac {21 \, \sqrt {2} \left (a c^{3}\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (2 \, x - \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{128 \, a c^{5}} - \frac {21 \, \sqrt {2} \left (a c^{3}\right )^{\frac {3}{4}} \log \left (x^{2} + \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{256 \, a c^{5}} + \frac {21 \, \sqrt {2} \left (a c^{3}\right )^{\frac {3}{4}} \log \left (x^{2} - \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{256 \, a c^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10/(c*x^4+a)^3,x, algorithm="giac")

[Out]

-1/32*(11*c*x^7 + 7*a*x^3)/((c*x^4 + a)^2*c^2) + 21/128*sqrt(2)*(a*c^3)^(3/4)*arctan(1/2*sqrt(2)*(2*x + sqrt(2
)*(a/c)^(1/4))/(a/c)^(1/4))/(a*c^5) + 21/128*sqrt(2)*(a*c^3)^(3/4)*arctan(1/2*sqrt(2)*(2*x - sqrt(2)*(a/c)^(1/
4))/(a/c)^(1/4))/(a*c^5) - 21/256*sqrt(2)*(a*c^3)^(3/4)*log(x^2 + sqrt(2)*x*(a/c)^(1/4) + sqrt(a/c))/(a*c^5) +
21/256*sqrt(2)*(a*c^3)^(3/4)*log(x^2 - sqrt(2)*x*(a/c)^(1/4) + sqrt(a/c))/(a*c^5)

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Mupad [B]
time = 1.07, size = 83, normalized size = 0.37 \begin {gather*} \frac {21\,\mathrm {atan}\left (\frac {c^{1/4}\,x}{{\left (-a\right )}^{1/4}}\right )}{64\,{\left (-a\right )}^{1/4}\,c^{11/4}}-\frac {\frac {11\,x^7}{32\,c}+\frac {7\,a\,x^3}{32\,c^2}}{a^2+2\,a\,c\,x^4+c^2\,x^8}-\frac {21\,\mathrm {atanh}\left (\frac {c^{1/4}\,x}{{\left (-a\right )}^{1/4}}\right )}{64\,{\left (-a\right )}^{1/4}\,c^{11/4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^10/(a + c*x^4)^3,x)

[Out]

(21*atan((c^(1/4)*x)/(-a)^(1/4)))/(64*(-a)^(1/4)*c^(11/4)) - ((11*x^7)/(32*c) + (7*a*x^3)/(32*c^2))/(a^2 + c^2
*x^8 + 2*a*c*x^4) - (21*atanh((c^(1/4)*x)/(-a)^(1/4)))/(64*(-a)^(1/4)*c^(11/4))

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